Answer:
Explanation:
There are eight moles of oxygen atoms in each mole of Fe3(PO4)2 . To answer this question, you must convert the given mass of Fe3(PO4)2 to moles of Fe3(PO4)2 . Then multiply the moles of Fe3(PO4)2 times (8mol O)/(1 mol Fe3(PO4)2) to determine the number of moles of oxygen. Then multiply the moles of oxygen times 6.022×1023 atoms O .
Given/Known:
massFe3(PO4)2 = 120.23 g
molar massFe3(PO4)2 = 357.478g/mol
1 moleFe3(PO4)2 contains 8 moles oxygen atoms
1 mole O atoms =6.022×1023 atoms
mass
molar mass
1 mole
1 mole O atoms =
Unknown:
number of oxygen atoms in120.23g Fe3(PO4)2
number of oxygen atoms in
Solution:
1. Convert given mass of Fe3(PO4)2 to moles.
2. Convert moles Fe3(PO4)2 to moles O.
3. Convert moles O to atoms O.
SOURCE : https://socratic.org/questions/5473b86c581e2a14bf83682d
Q2: How many atoms of carbon are in 0.0235 gof cocaine hydrochloride, C17H22ClNO4?
0.0235 g C17H22ClNO4 represents a fraction of a mole.
Moles of Cocaine Hydrochloride
Atoms of Carbon
SOURCE :https://socratic.org/questions/592c925811ef6b2834ec19cb
Q2: How many atoms of carbon are in 0.0235 gof cocaine hydrochloride, C17H22ClNO4?
Answer:
There are 7.08×1020.atoms C in 0.0235 g C17H22ClNO4 .
Explanation:
The molecular formula for cocaine hydrochloride, C17H22ClNO4 , tells us that one mole of C17H22ClNO4 contains 17 mol C .
In order to determine the mol C17H22ClNO34 in 0.0235 g C17H22ClNO4 , divide its given mass by its molar mass by multiplying by its inverse.
The molar mass of C17H22ClNO4 is 339.816 g/mol .
https://www.ncbi.nlm.nih.gov/pccompound?term=%22COCAINE+HYDROCHLORIDE%22
https://www.ncbi.nlm.nih.gov/pccompound?term=%22COCAINE+HYDROCHLORIDE%22
Divide its given mass by its molar mass by multiplying by its inverse.
0.0235g C17H22ClNO4×1mol C17H22ClNO4339.816g C17H22ClNO4=0.00006916 mol C17H22ClNO4
Multiply mol C17H22ClNO4 by 17 mols C divided by 1 mol C17H22ClNO4 , then multiply by 6.022×1023 atoms/mol .
0.000069161mol C17H22ClNO4×17mol C1mol C17H22ClNO4=0.00117572 mol C 0.00117572mol C×6.022×1023atoms C1mol C =7.08×1020atoms C , rounded to three significant figures
SOURCE :https://socratic.org/questions/592c925811ef6b2834ec19cb
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