MOLE : ANSWER & EXPLANATION

How many atoms of each element of $AgN{O}_3$ are in 0.15 mol of $AgN{O}_3$?

Answer:

$9.0\text{x}{10}^{22}\text{Ag atoms}$

$9.0\text{x}{10}^{22}\text{N atoms}$

$2.7\text{x}{10}^{23}\text{O atoms}$

SOURCE :https://socratic.org/questions/how-many-atoms-of-each-element-of-agno-3-are-in-0-15-mol-of-agno-3

Explanation:

1. From 0.15mol of $AgN{O}_3$, we can find the moles of each element by counting how many of each element is present in the entire compound. In $AgN{O}_3$, there's 1 Ag, 1 N and 3 O.
2. Then, we convert from moles of each element to the number of atoms using Avogadro's number $6.02\text{x}{10}^{23}$.

I went ahead and set up the two steps above in 1 line for each element:
$\text{Ag atoms}=0.15\text{mol}AgN{O}_3\cdot \frac{1\text{mol}Ag}{1\text{mol}AgN{O}_3}\cdot \frac{6.02\text{x}{10}^{23}\text{Ag atoms}}{1\text{mol}Ag}=9.0\text{x}{10}^{22}\text{Ag atoms}$

$\text{N atoms}=0.15\text{mol}AgN{O}_3\cdot \frac{1\text{mol}N}{1\text{mol}AgN{O}_3}\cdot \frac{6.02\text{x}{10}^{23}\text{N atoms}}{1\text{mol}N}=9.0\text{x}{10}^{22}\text{N atoms}$

$\text{O atoms}=0.15\text{mol}AgN{O}_3\cdot \frac{3\text{mol}O}{1\text{mol}AgN{O}_3}\cdot \frac{6.02\text{x}{10}^{23}\text{O atoms}}{1\text{mol}O}=2.7\text{x}{10}^{23}\text{O atoms}$